How do you graph using slope and intercept of 8y-7x=13?

1 Answer
Jun 2, 2018

y = 7/8x + 13/8 [original, as fractions]
y = 0.875x + 1.625 [as decimals]

Explanation:

8y - 7x = 13

The goal is to make 8y - 7x = 13 into y = mx + b format in order to easily graph it. To do this, we're going to rearrange the current equation.

8y - 7x = 13

First, let's make -7x to go the other side so that way the equation comes closer to the y = mx + b form. To do this, add 7x to both sides to cancel out -7x. You should now have:

8y = 7x + 13

Now, we need to isolate for y. To do this, divide 8y by 8. Because you must do to one side to the other, you'll divide the entire equation by 8.

y = 7/8x + 13/8
7/8x is your slope and 13/8 is your y-intercept. To make it easier to calculate, I'll convert them into decimals.

y = 0.875x + 1.625

You can either graph it by estimating using the decimals provided, or you can use the original version with rise over run. Here's what it looks like:

graph{y = 7/8x + 13/8 [-12.66, 12.65, -6.33, 6.33]}