How do you graph the line #y = 4/5x + 3#?

2 Answers
Jul 16, 2018

Assign value for x to find y.

Explanation:

If x is zero, #y=3#

If x is 1, #y=3.8#

If x is 2, #y=4.6#

etc.

You can graph now:

graph{((4x)/5)+3 [-8.04, 11.96, -2.4, 7.6]}

Jul 16, 2018

Refer to the explanation.

Explanation:

Graph:

#y=4/5x+3#

You only need two points to graph a straight line. The most convenient points are the x- and y-intercepts.

Y-intercept: value of #y# when #x=0#

Substitute #0# for #x# and solve for #y#.

#y=4/5(0)+3#

#y=3#

The y-intercept is the point #(0,3)#. Plot this point.

X-intercept: value of #x# when #y=0#

Substitute #0# for #y# and solve for #x#.

#0=4/5x+3#

Multiply both sides by #5#.

#0=4x+3xx5#

#0=4x+15#

Subtract #15# from both sides.

#-15=4x#

Divide both sides by #4#.

#-15/4=x#

Switch sides.

#x=-15/4# or #x=-3.75#

The x-intercept is the point #(-15/4,0)# or #x=(-3.75,0)#. Plot this point.

You now have two points plotted. Draw a straight line through the points.

graph{y=4/5x+3 [-10, 10, -5, 5]}