At what point does the line (3,4) (6,5) cross the X axis?

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Answer 1 · 2018-06-06T12:08:39

Crossing point on x-axis is $(- 9, 0)$ $(-9,0)$

The slope of the line passing through $(3, 4) and (6, 5)$ $(3,4) and (6,5)$ is

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - 4}{6 - 3} = \frac{1}{3}$ $m= (y_2-y_1)/(x_2-x_1)= (5-4)/(6-3)=1/3$

The equation of line passing through $(3, 4)$ $(3,4)$ having slope of

$m = \frac{1}{3}$ $m=1/3$ is $y - y_{1} = m (x - x_{1}) or y - 4 = \frac{1}{3} (x - 3)$ $y-y_1=m(x-x_1) or y-4=1/3(x-3)$ . or

$3 y - 12 = x - 3 or x - 3 y = - 9$ $3 y -12= x -3 or x- 3 y = -9$ Therefore, the equation of

line is $x - 3 y = - 9$ $x- 3 y = -9$ . When it crosses x-axis the y coordinate

is $0 :. x- 3*0 =-9 or x= -9$ Therefore ,crossing point on

x-axis is $(-9,0)$

graph{x - 3 y = -9 [-10, 10, -5, 5]}