How can you graph the linear equation x=y+3?

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Answer 1 · 2017-06-12T03:29:54

See the explanation.

Graph:

$x = y + 3$ $x=y+3$

Solve for $y$ $y$ to get the slope intercept form: $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

Subtract $y$ $y$ from both sides.

$- y + x = 3$ $-y+x=3$

Subtract $x$ $x$ to both sides.

$- y = - x + 3$ $-y=-x+3$

Multiply both sides by $- 1$ $-1$ .

$y = x - 3$ $y=x-3$

Now determine several points on the line by choosing values for $x$ $x$ and solving for $y$ $y$ .

$Points$ $"Points"$

$x = - 2,$ $x=-2,$ $y = - 5$ $y=-5$

$x = 0,$ $x=0,$ $y = - 3$ $y=-3$

$x = 2,$ $x=2,$ $y = - 1$ $y=-1$

Plot the points and draw a straight line through the them. graph{y=x-3 [-16.02, 16, -8.01, 8.01]}