How do you find slope and intercepts to graph $2x-3y=3$ ?

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Answer 1 · 2018-07-16T11:06:48

Slope $=2/3$ , x-intercept $=3/2$ & y-intercept $=-1$

The given straight line:

$2x-3y=3$

$y=2/3 x-1$

Comparing above equation with the standard form of slope-intercept: $y=mx+c$ , we get

Slope: $m=2/3$

Re-writing the equation of straight line as follows

$x/{3/2}+y/{-1}=1$

Comparing above equation with the intercept form: $x/a+y/b=1$ , we get

x-intercept: $a=3/2$

y-intercept: $b=-1$

How do you find slope and intercepts to graph 2x-3y=32x-3y=3?