How do you find slope and intercepts to graph #2x-3y=3#?

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Answer 1 · 2018-07-16T11:06:48

Slope #=2/3#, x-intercept #=3/2# & y-intercept #=-1#

The given straight line:

#2x-3y=3#

#y=2/3 x-1#

Comparing above equation with the standard form of slope-intercept: #y=mx+c# , we get

Slope: #m=2/3#

Re-writing the equation of straight line as follows

#x/{3/2}+y/{-1}=1#

Comparing above equation with the intercept form: #x/a+y/b=1#, we get

x-intercept: #a=3/2#

y-intercept: #b=-1#