How do you find slope and intercepts to graph $2 x - 3 y = 3$ $2x-3y=3$ ?

Question

6309 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-16T11:06:48

Slope $= \frac{2}{3}$ $=2/3$ , x-intercept $= \frac{3}{2}$ $=3/2$ & y-intercept $= - 1$ $=-1$

The given straight line:

$2 x - 3 y = 3$ $2x-3y=3$

$y = \frac{2}{3} x - 1$ $y=2/3 x-1$

Comparing above equation with the standard form of slope-intercept: $y = m x + c$ $y=mx+c$ , we get

Slope: $m = \frac{2}{3}$ $m=2/3$

Re-writing the equation of straight line as follows

$\frac{x}{\frac{3}{2}} + \frac{y}{- 1} = 1$ $x/{3/2}+y/{-1}=1$

Comparing above equation with the intercept form: $\frac{x}{a} + \frac{y}{b} = 1$ $x/a+y/b=1$ , we get

x-intercept: $a = \frac{3}{2}$ $a=3/2$

y-intercept: $b = - 1$ $b=-1$

How do you find slope and intercepts to graph 2x−3y=32x-3y=3?