How do you find slope and intercepts to graph $4 x + 3 y = - 3$ $4x+3y=-3$ ?

Question

2569 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-08T03:43:08

Slope $= \frac{- 4}{3}$ $=(-4)/3$

Y-Intercept $= - 1$ $=-1$

The given equation is in the form -

$a x + b y = c$ $ax+by=c$

To find its slope use the formula

$m = \frac{- a}{b} = \frac{- 4}{3}$ $m=(-a)/b=(-4)/3$

To find its intercept , put $x = 0$ $x=0$

At $x = 0; 4 (0) + 3 y = - 3$ $x=0; 4(0)+3y =-3$

$3 y = - 3$ $3y=-3$
$y = \frac{- 3}{3} = - 1$ $y=(-3)/3=-1$

Slope $= \frac{- 4}{3}$ $=(-4)/3$

Y-Intercept $= - 1$ $=-1$

How do you find slope and intercepts to graph 4x+3y=−34x+3y=-3?