How do you find slope and intercepts to graph 9x−5y=4?

1 Answer
Sirach
Jun 20, 2018

m=95; with points (0,−45) and (1,1)

Explanation:

Convert the equation into slope-intercept form by solving for y.

−5y=−9x+4 => subtracting both sides by -9x

y=95x−45 = > dividing by -5

The slope-intercept equation takes the form of y=mx+b. The slope m would be the coefficient of x, and the constant b, the y-intercept (value of y if x=0), thus yielding: m=95 and b=−45.

This gives us one point on the line: (0,−45).

To get another point on the line, substitute any number for x and solve for y. For ease in graphing, choose an integer close to the first point. For this example, let x=1.

y=95⋅(1)−45 => by substitution
y=95−45=55or1

Thus, point (1,1) also belongs to the line. From here, the two points can be connected, and a line can be formed accordingly.

graph{9x-5y=4 [-2.657, 2.657, -1.328, 1.328]}

Source: https://www.mathplanet.com/education/algebra-1/formulating-linear-equations/writing-linear-equations-using-the-slope-intercept-form

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