How do you find slope and intercepts to graph $F (t) = 3 - (\frac{8}{3} t)$ $F(t)= 3- (8/3t)$ ?

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Answer 1 · 2018-05-29T19:55:29

Slope: - $\frac{8}{3}$ $8/3$
x-int: $\frac{9}{8}$ $9/8$
y-int: 3

slope is the number in front of t which is

x-int set function = 0 and solve for t: $\frac{8}{3}$ $8/3$
0=3 - $\frac{8}{3}$ $8/3$ t
$\frac{8}{3}$ $8/3$ t = 3
t = $\frac{9}{8}$ $9/8$

y-int set t = 0
3 - $\frac{8}{3}$ $8/3$ (0)
= 3

How do you find slope and intercepts to graph F(t)=3−(83t)F(t)= 3- (8/3t)?