Question

How do you find the linearization at a=1 of `f(x) = ln(x)`?

Answer 1

`L=x`

Explanation:

`L=f(a)+f'(a)(x-a)`

`f(x) = lnx`

`f(a) = f(1) =0`

`f'(x) = 1/x`

`f'(a) = f'(1) = 1/1=1`

`L=x`