How do you find the slope and intercept to graph $4 x + 3 y - 7 = 0$ $4x+3y-7=0$ ?

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Answer 1 · 2018-04-27T12:55:21

$m = \frac{4}{3}$ $m = 4/3$

$y-int$ $"y-int"$ = $\frac{7}{3}$ $7/3$

$4 x + 3 y - 7 = 0$ $4x+3y-7=0$

rearrange into $y = m x + b$ $y=mx+b$

$3 y = - 4 x + 7$ $3y=-4x+7$

$y = \frac{4 x}{3} + \frac{7}{3}$ $y=(4x)/3+(7)/3$

$:.$ slope is 4/3

$4x+3y-7=0$

$y=(4x)/3+(7)/3$

sub $x=0$

$y=(4(0))/3+(7)/3$
$y=0+(7)/3$
$y=(7)/3$

$:.$ $(0, 7/3)$

graph{4x+3y-7=0 [-10, 10, -5, 5]}

How do you find the slope and intercept to graph 4x+3y-7=04x+3y−7=04x+3y-7=0?