How do you find the slope and intercept to graph $7 x - 2 y = 10$ $7x - 2y = 10$ ?

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Answer 1 · 2018-04-07T02:44:09

Put it in slope-intercept form.

$y = \frac{7}{2} x - 5$ $y = 7/2 x - 5$

$y$ $y$ -intercept $= - 5$ $= -5$

slope $= \frac{7}{2}$ $= 7/2$

Put the equation into slope-intercept form by moving the $- 2 y$ $-2y$ on the right side of the equation.

$7 x = 2 y + 10$ $7x = 2y + 10$

Then move the $10$ $10$ to the left side

$7 x - 10 = 2 y$ $7x - 10 = 2y$

Now divide all values by $2$ $2$ .

$\frac{7}{2} - \frac{10}{2} = (2 \frac{y}{2})$ $7/2 - 10/2 = (2y/2)$

to get

$\frac{7}{2} x - 5 = y$ $7/2x - 5 = y$

How do you find the slope and intercept to graph 7x−2y=107x - 2y = 10?