How do you find the slope and intercept to graph $x - 27 = 6$ $x-27=6$ ?

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Answer 1 · 2016-02-23T15:20:13

Only 1 intercept and that is $x = 33$ $x=33$
The slope is undefined.

First off, notice that there is no $y$ $y$ as in standard form of straight line graph equation: $y = m x + c$ $y=mx+c$ where m represents the slope

That in itself is a clue!

Add 27 to both sides

$x - 27 + 27 = 6 + 27$ $x-27+27=6+27$

$x + 0 = 33$ $x+0=33$

$x = 33$ $x=33$

In this form the equation is that of a line perpendicular to the x-axis passing through $x = 33$ $x=33$

The term slop implies change in y related to change in x

So we have: $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $" "m= (y_2-y_1)/(x_2-x_1)$

But $x$ $x$ is fixed at 33 so we have

$m = \frac{y_{2} - y_{1}}{33 - 33}$ $m= (y_2-y_1)/(33-33)$

$m = \frac{y_{2} - y_{1}}{0}$ $m= (y_2-y_1)/0$ mathematically you are 'not allowed' to divide by 0

The technical term for this 'not defined'

So the slope is not defined

Tony B

How do you find the slope and intercept to graph x−27=6x-27=6?