How do you find the slope and y intercept to sketch $3 y + 5 = 0$ $3y+5=0$ ?

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Answer 1 · 2016-08-10T16:53:10

A horizontal line through $y = - \frac{5}{3}$ $y = -5/3$

Write the equation in the form $y = m x + c$ $y = mx + c$ because then we can read off the slope and the y-intercept immediately.

$3 y = - 5$ $3y = -5$

$y = - \frac{5}{3} \Rightarrow y = 0 x - \frac{5}{3}$ $y = -5/3 rArr y = 0x -5/3$

There is no x-term which means that the slope is zero. This is a horizontal line. The y-intercept is $- \frac{5}{3}$ $-5/3$

How do you find the slope and y intercept to sketch 3y+5=03y+5=0?