How do you graph #2x-y=4#?
1 Answer
Jun 22, 2016
Calculate a few coordinate points that satisfy the given equation;
plot those points;
draw a line through the plotted points.
Explanation:
Given
And picking some (arbitrary)
We can solve for
#y# using these values of#x#
#{: (underline(x),,underline(y)), (0,rarr,-4), (1,rarr,-2), (2,rarr,0) :}#
which provides the coordinates
Plotting these points and drawing a line through them:
graph{(x^2+(y+4)^2-0.02)((x-1)^2+(y+2)^2-0.02)((x-2)^2+y^2-0.02)(2x-y-4)=0 [-6.784, 9.02, -5.576, 2.33]}