How do you graph 3x+y= -2?

1 Answer
Jun 15, 2018

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For x = 0

(3 * 0) + y = -2

0 + y = -2

y = -2 or (0, -2)

Second Point: For y = 1

3x + 1 = -2

3x + 1 - color(red)(1) = -2 - color(red)(1)

3x + 0 = -3

3x = -3

(3x)/color(red)(3) = -3/color(red)(3)

x = -1 or (-1, 1)

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.035)((x+1)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + y + 2)(x^2+(y+2)^2-0.035)((x+1)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}