How do you graph #6x-4y=16#?
1 Answer
Aug 31, 2017
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point:
For
Second Point:
For
We can next graph the two points on the coordinate plane:
graph{(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(6x-4y-16)(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}