How do you graph the equation #3x+8y=32#?
1 Answer
Sep 28, 2017
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next graph the two points on the coordinate plane:
graph{(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(3x+8y-32)(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}