How do you graph the equation #3x+8y=32#?

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Answer 1 · 2017-09-28T17:38:20

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) + 8y = 32#

#0 + 8y = 32#

#8y = 32#

#(8y)/color(red)(8) = 32/color(red)(8)#

#y = 4# or #(0, 4)#

Second Point: For #x = 8#

#(3 * 8) + 8y = 32#

#24 + 8y = 32#

#-color(red)(24) + 24 + 8y = -color(red)(24) + 32#

#0 + 8y = 8#

#8y = 8#

#(8y)/color(red)(8) = 8/color(red)(8)#

#y = 1# or #(8, 1)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x+8y-32)(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}