How do you graph the equation 3x+8y=32?

1 Answer
Sep 28, 2017

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For x=0

(30)+8y=32

0+8y=32

8y=32

8y8=328

y=4 or (0,4)

Second Point: For x=8

(38)+8y=32

24+8y=32

24+24+8y=24+32

0+8y=8

8y=8

8y8=88

y=1 or (8,1)

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x+8y-32)(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}