How do you graph the equation #-x+3y=9#?

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Answer 1 · 2018-05-30T12:37:09

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(-0) + 3y = 9#

#0 + 3y = 9#

#3y = 9#

#(3y)/color(red)(3) = 9/color(red)(3)#

#y = 3# or #(0, 3)#

Second Point: For #y = 0#

#-x + (3 * 0) = 9#

#-x + 0 = 9#

#-x = 9#

#color(red)(-1) xx x = color(red)(-1) xx 9#

#x = -9# or #(-9, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x+9)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(-x + 3y - 9)(x^2+(y-3)^2-0.035)((x+9)^2+y^2-0.035)=0 [-10, 10, -5, 5]}