How do you graph the equation #y=1/2x+6#?

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Answer 1 · 2017-10-29T17:25:37

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (1/2 * 0) + 6#

#y = 0 + 6#

#y = 6# or #(0, 6)#

Second Point: For #x = 2#

#y = (1/2 * 2) + 6#

#y = 1 + 6#

#y = 7# or #(2, 7)#
We can next plot the two points on the coordinate plane:

graph{(x^2+(y-6)^2-0.075)((x-2)^2+(y-7)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - (1/2)x-6)(x^2+(y-6)^2-0.075)((x-2)^2+(y-7)^2-0.075)=0 [-20, 20, -10, 10]}