How do you graph using slope and intercept of $\frac{1}{3} x + \frac{1}{4} y = \frac{7}{6}$ $1/3x + 1/4y = 7/6$ ?

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How do you graph using slope and intercept of $\frac{1}{3} x + \frac{1}{4} y = \frac{7}{6}$ $1/3x + 1/4y = 7/6$ ?

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Answer 1 · 2018-03-28T20:20:36

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Explanation:

$\frac{1}{4} y = - \frac{1}{3} x + \frac{7}{6}$ $1/4y=-1/3x+7/6$ Set to slope-intercept form $y = m x + b$ $y=mx+b$
$y = - \frac{4}{3} x + \frac{28}{6}$ $y=-4/3x+28/6$ multiply whole equation by 4 so that y is isolated
$y = - \frac{4}{3} x + \frac{14}{3}$ $y=-4/3x+14/3$ reduce graph{y=-4/3x+14/3 [-10, 10, -5, 5]}

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How do you graph using slope and intercept of $\frac{1}{3} x + \frac{1}{4} y = \frac{7}{6}$ $1/3x + 1/4y = 7/6$ ?

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How do you graph using slope and intercept of $\frac{1}{3} x + \frac{1}{4} y = \frac{7}{6}$ $1/3x + 1/4y = 7/6$ ?