How do you graph using slope and intercept of $-1x - 6y = 4$ ?

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Answer 1 · 2017-06-02T16:54:03

See below.

$y=mx+b$

where $m$ is the slope and $b$ is the y-intercept.

$-1x-6y=4$

Add $1x$ to both sides of the equation.

$-6y=4+x$

$6y=-x-4$

Divide both sides of the equation by $6$ .

$y=(-1/6)x-4/6$

So this line has slope of $-1/6$ and a y-intercept of $-2/3$ .

graph{y= (-1/6)x-2/3 [-10, 10, -5, 5]}

How do you graph using slope and intercept of -1x - 6y = 4-1x - 6y = 4?