How do you graph using slope and intercept of $- 2 x + 3 y = - 19$ $-2x+3y=-19$ ?

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Answer 1 · 2018-04-15T04:16:38

Lets solve for $y$ $y$ :

$- 2 x + 3 y = - 19$ $-2x + 3y = -19$

Step 1 : Add $2 x$ $2x$ to the right side

$3 y = - 19 + 2 x$ $3y = -19 +2x$

Step 2: Get $y$ $y$ by it self so lets divide by $3$ $3$ to both sides

$\frac{3 y}{3} = \frac{- 19 + 2 x}{3}$ $(3y)/3 = (-19 +2x)/3$

$y = - \frac{19}{3} + \frac{2 x}{3}$ $y= -19/3 + (2x) /3$

Rearrange the equation to this format $y = m x + b$ $y = mx+b$

$y = \frac{2 x}{3} - \frac{19}{3}$ $y =(2x)/3 -19/3$

$y$ $y$ int would be your $b$ $b$

which $b = - \frac{19}{3}$ $b = -19/3$

slope intercept is your $m x$ $mx$
$m = \frac{2}{3}$ $m= 2/3$

How do you graph using slope and intercept of −2x+3y=−19-2x+3y=-19?