How do you graph using slope and intercept of $2 x + 7 y = - 40$ $2x+7y= - 40$ ?

Question

2004 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-08T02:37:58

By changing the equation to slope intercept form, which would be $y = - \frac{2}{7} x - \frac{40}{7}$ $y=-2/7x-40/7$

The general way to graph a line like this is to get it into slope intercept form which is $y = m x + b$ $y=mx+b$

So generally, just solve for y.

$2 x + 7 y = - 40$ $2x+7y=-40$
$7 y = - 2 x - 40$ $7y=-2x-40$
$y = - \frac{2}{7} x - \frac{40}{7}$ $y=-2/7x-40/7$

You may put it into decimals if you wish but it's not really necessary.

From this equation we can see that the slope is $- \frac{2}{7}$ $-2/7$ and the y intercept is $- \frac{40}{7}$ $-40/7$ .

The graph ends up looking like:
graph{y=-2/7x-40/7 [-29.01, 28.72, -11.67, 17.18]}

How do you graph using slope and intercept of 2x+7y=−402x+7y= - 40?