Question

How do you graph using slope and intercept of `2x-y=5`?

Answer 1

See below.

Explanation:

So we want it in slope which is `y=mx+b` but this is in standard form.

So let start by rewriting the equation

`2x-y=5`

Now, we subtract `2x` from both sides which gives us:

`-y=-2x+5`

Now, the variable `y` can never be a negative numbers, so we divide everything by negative one which changes the sign to this:

`y=2x-5`

Now, you can plug in any numbers for x that gives you an input for y.

So let plug in 2 values for x.

`y=2(-1)-5`
`y=-2-5` - Distribute the 2 to the number inside the parentheses
`y=-7`

So now we know when we plug in `-1` for x, we got a output of `y=-7` but we need to put this as a coordinate point so we can graph this.

So to do this, it goes like this `(x, y)`. So whatever you plug in for x, you put it as the first number. Output is where you put it in the second place.

So let plug in 7 for x this time.

`y=2(7)-5`
`y=14-5`
`y=9`

So we need to put this as a coordinate point which would be `(7,9)`.

The y-intercept of this equation is `(0,-5)`

Your graph will look like this:
graph{y=2x-5 [-10, 10, -5, 5]}

Ensure that you use a straight edge or something that is straight to draw a straight line.