How do you graph using slope and intercept of $- 3 x + 7 y = - 1$ $-3x+7y=-1$ ?

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Answer 1 · 2018-07-13T13:26:15

As below.

Standard form of equation for slope-intercept is $y = m x + c$ $y = mx + c$

Slope = m, y-intercept = c.

$- 3 x + 7 y = - 1$ $-3x + 7y = -1$

$7 y = 3 x - 1$ $7y = 3x - 1$

$y = (\frac{3}{7}) x - (\frac{1}{7})$ $y = (3/7)x - (1/7)$

graph{(3/7)x - 1/7 [-10, 10, -5, 5]}

How do you graph using slope and intercept of −3x+7y=−1-3x+7y=-1?