How do you graph using slope and intercept of #4x-2y=48#?

2 Answers
Jun 18, 2018

Put it into the form #y=mx+c#

#4x=2y+48#

#4x-48=2y#

#2x-24=y#

#y=2x-24#

slope is 2 and the intercept is (0,-24)

Jun 18, 2018

See below for graph and method

Explanation:

Re-arranging the given equation: #4x-2y=48# into slope-intercept form:
#color(white)("XXX")4x-48=2y#

#color(white)("XXX")y=2x-24#
#color(white)("XXX")# which is the slope intercept form
#color(white)("XXX")# with slope #2#, and
#color(white)("XXX ")y#-intercept #(-24)#

The #y# intercept of #(-24)# tells us that one of the points on our line is at #(x_0,y_0)=(0,-24)#

The slope of #2# tells us that for every increase of #1# in the value of #x#, the value of #y# will increase by #2#.
So some other points that we could use to plot out line are:
#color(white)("XXX")(x_1,y_1)=(0+1,-24+2)=(1,-22)#
or
#color(white)("XXX")(x_24,y_24)=(0+24,-24+(2 * 24))=(24,24)#

graph{(x^2+(y+24)^2-0.3)((x-1)^2+(y+22)^2-0.3)((x-24)^2+(y-24)^2-0.3)(4x-2y-48)=0 [-50.63, 81, -40.23, 25.64]}