How do you graph using slope and intercept of 4x2y=48?

2 Answers
Jun 18, 2018

Put it into the form y=mx+c

4x=2y+48

4x48=2y

2x24=y

y=2x24

slope is 2 and the intercept is (0,-24)

Jun 18, 2018

See below for graph and method

Explanation:

Re-arranging the given equation: 4x2y=48 into slope-intercept form:
XXX4x48=2y

XXXy=2x24
XXX which is the slope intercept form
XXX with slope 2, and
XXX y-intercept (24)

The y intercept of (24) tells us that one of the points on our line is at (x0,y0)=(0,24)

The slope of 2 tells us that for every increase of 1 in the value of x, the value of y will increase by 2.
So some other points that we could use to plot out line are:
XXX(x1,y1)=(0+1,24+2)=(1,22)
or
XXX(x24,y24)=(0+24,24+(224))=(24,24)

graph{(x^2+(y+24)^2-0.3)((x-1)^2+(y+22)^2-0.3)((x-24)^2+(y-24)^2-0.3)(4x-2y-48)=0 [-50.63, 81, -40.23, 25.64]}