How do you graph using slope and intercept of #4x-2y=48#?
2 Answers
Put it into the form
slope is 2 and the intercept is (0,-24)
See below for graph and method
Explanation:
Re-arranging the given equation:
The
The slope of
So some other points that we could use to plot out line are:
or
graph{(x^2+(y+24)^2-0.3)((x-1)^2+(y+22)^2-0.3)((x-24)^2+(y-24)^2-0.3)(4x-2y-48)=0 [-50.63, 81, -40.23, 25.64]}