Question

How do you graph using slope and intercept of `- 5x + y =0`?

Answer 1

You have to move some things around in the equation to put it into slope-intercept form, then you can graph it.

Explanation:

`-5x+y=0`

Slope intercept form is: `y=mx+b`

First, you need to get the `y` alone on the left side of the equation.
`-5x+y=0`
`-5x+y+5x=0+5x`
`y=0+5x`

Now, the equation is almost correct and ready to be graphed, but for it to be technically correct, the place of the `0` and the `5x` need to be switched.
`y=5x+0`

So, you know that the y-intercept is `0`, which means that it is at the point `(0,0)`
Plot a point at `(0,0)`

Then, since you have a slope of `5`, that means you have a rise, or change in the `y` value, of `+5`, and a run, or change in the `x` value, of `+1`

Starting at point `(0,0)`, plot at point five up, and one to the right. So, that point would be at `(1,5)`. Then, from `(1,5)`, go up five, and to the right one, so you'll be at point `(2,10)`. Then, draw a line through your points.