Question

How do you graph using slope and intercept of `6x + 5y = 2`?

Answer 1

See below:

Explanation:

First, rewrite it in slope intercept form: `y=mx+b`:

Subtract `6x` on both sides:

`5y=2-6x`

Now divide by `5`

`y=2/5-6/5x`

Rewrite it so the `x` comes first:

`y=-6/5x+2/5`

Now our equation is in the form `y=mx+b`. The `m` which is `-6/5` represents the slope and the `2/5` represents the y-intercept. So make a point on `(0,2/5)` and then move left `6` units of `x` and go up `5` units of `y`. Then, connect the dots:

graph{y=(-6/5)x+(2/5) [-10, 10, -5, 5]}