How do you graph using slope and intercept of $- 7 x + y = - 19$ $-7x+y=-19$ ?

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How do you graph using slope and intercept of $- 7 x + y = - 19$ $-7x+y=-19$ ?

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Answer 1 · 2015-11-05T13:20:09

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Explanation:

Note that this is an equation of line.

Also

$- 7 x + y = - 19$ $-7x +y = - 19$
$\Rightarrow \frac{7 x}{19} + \frac{y}{- 19} = 1$ $implies (7x)/(19)+y/(-19) = 1$
$\Rightarrow \frac{x}{\frac{19}{7}} + \frac{y}{- 19} = 1$ $implies x/(19/7)+y/(-19) = 1$

So this line passes through $(0, - 19)$ $(0,-19)$ and $(\frac{19}{7}, 0)$ $(19/7,0)$ . So, draw a line joining these two points gives you the graph of the equation.

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How do you graph using slope and intercept of $- 7 x + y = - 19$ $-7x+y=-19$ ?

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Science

Math

Humanities

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How do you graph using slope and intercept of −7x+y=−19-7x+y=-19?

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Explanation:

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How do you graph using slope and intercept of $- 7 x + y = - 19$ $-7x+y=-19$ ?