Question

How do you graph using slope and intercept of `8y-7x=13`?

Answer 1

`y = 7/8x + 13/8` [original, as fractions]
`y = 0.875x + 1.625` [as decimals]

Explanation:

`8y - 7x = 13`

The goal is to make `8y - 7x = 13` into `y = mx + b` format in order to easily graph it. To do this, we're going to rearrange the current equation.

`8y - 7x = 13`

First, let's make `-7x` to go the other side so that way the equation comes closer to the `y = mx + b` form. To do this, add `7x` to both sides to cancel out `-7x`. You should now have:

`8y = 7x + 13`

Now, we need to isolate for `y`. To do this, divide `8y` by `8`. Because you must do to one side to the other, you'll divide the entire equation by `8`.

`y = 7/8x + 13/8`
`7/8x` is your slope and `13/8` is your y-intercept. To make it easier to calculate, I'll convert them into decimals.

`y = 0.875x + 1.625`

You can either graph it by estimating using the decimals provided, or you can use the original version with rise over run. Here's what it looks like:

graph{y = 7/8x + 13/8 [-12.66, 12.65, -6.33, 6.33]}