How do you graph using slope and intercept of #8y-7x=13#?

1 Answer
Jun 2, 2018

#y = 7/8x + 13/8# [original, as fractions]
#y = 0.875x + 1.625# [as decimals]

Explanation:

#8y - 7x = 13#

The goal is to make #8y - 7x = 13# into #y = mx + b# format in order to easily graph it. To do this, we're going to rearrange the current equation.

#8y - 7x = 13#

First, let's make #-7x# to go the other side so that way the equation comes closer to the #y = mx + b# form. To do this, add #7x# to both sides to cancel out #-7x#. You should now have:

#8y = 7x + 13#

Now, we need to isolate for #y#. To do this, divide #8y# by #8#. Because you must do to one side to the other, you'll divide the entire equation by #8#.

#y = 7/8x + 13/8#
#7/8x# is your slope and #13/8# is your y-intercept. To make it easier to calculate, I'll convert them into decimals.

#y = 0.875x + 1.625#

You can either graph it by estimating using the decimals provided, or you can use the original version with rise over run. Here's what it looks like:

graph{y = 7/8x + 13/8 [-12.66, 12.65, -6.33, 6.33]}