Question

How do you graph using slope and intercept of `x+2y=5`?

Answer 1

`y=-0.5x+2.5`. Slope = `-0.5`, intercepts: `(0, 2.5)`, `(5, 0)`
graph{y=-0.5x+2.5 [-10, 10, -5, 5]}

Explanation:

`x+2y=5`
To get slope and intercept you need to rewrite the function so that y is to the left and expressed as a function of x, like this:
`2y=-x+5` (Subtract x on both sides of the equal sign)
`y=-1/2x+2 1/2` (divide both sides with 2)

Here the slope is `-1/2` (the constant in front of x).

We see that this graph intersects the y axis at `y= 2 1/2` when `x = 0`
and the x axis at `x=5` when y=0.

This gives the following graph:
graph{y=-0.5x+2.5 [-2.203, 6.57, -0.86, 3.523]}