Question

How do you graph using slope and intercept of `-x+5y=-5`?

Answer 1

The slope is `1/5`.
The y-intercept is `-1`.
The x-intercept is `5`.

Explanation:

`-x+5y=-5` is a linear equation in standard form. Convert it to the slope intercept form by solving for `y`.

`-x+5y=-5`

Add `x` to both sides.

`5y=x-5`

Divide both sides by `5`.

`y=x/5-5/5=`

`y=1/5x-1`

`y=1/5x-1` is the slope intercept form of a linear equation, `y=mx+b`, where `m` is the slope, `1/5` and `b` is the y-intercept, `-1`.

The y-intercept is the value of `y` when `x=0`. The point of the y-intercept is `(0,-1)`.

The x-intercept is the value of `x` when `y=0`.

`0=1/5x-1`

Add `1` to both sides.

`1=1/5x`

Multiply both sides times `5`.

`1*5=1/cancel5x*cancel5=`

`5=x`

Switch sides.

`x=5`

The x-intercept is `5`. The point of the x-intercept is `(5,0)`.

Plot the two points and draw a straight line through the points.

graph{y=1/5x-1 [-16.02, 16, -8.01, 8.01]}