How do you graph using the intercepts for $x - 2 y = 8$ $x-2y=8$ ?

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Answer 1 · 2018-03-18T20:35:26

$y = \frac{1}{2} x - 4$ $y = 1/2x - 4$

Recall the formula for a linear equation:

$y = m x + b$ $y = mx + b$

So

$x - 2 y = 8$ $x - 2y = 8$

$- 2 y = 8 - x$ $-2y = 8 - x$

$y = \frac{1}{2} x - 4$ $y = 1/2x - 4$

Using the $y$ $y$ -intercept of $- 4$ $-4$ , plot this on your graph.

graph{y = 1/2x -4 [-10, 10, -5, 5]}

$\frac{1}{2} = \frac{Rise}{Run}$ $1/2 = "Rise"/"Run"$

Continue to plot points on the graph, moving up one value once, and right a value twice.

Hope this helps. :)

How do you graph using the intercepts for x−2y=8 x-2y=8?