How do you graph y = 1/2x- 6 using the slope and intercept?

1 Answer
May 22, 2017

See explanation.

A lot of method detail given. The actual calculation is a lot faster than given once you are used to equations of this type.

Explanation:

Given: y=1/2x-6

Compare to the standardised form of y=mx+c

color(blue)("Teaching bit about gradient")

Where m->" gradient"->("change in y")/("change in x")

Note that the gradient is consequential to reading left to write on the x-axis. This is important as it indicates if the graph is like 'going up a hill' or if it is like 'going down a hill' left to right.

Negative gradient is going down y->" becomes less"
Positive gradient is going up y->" becomes greater"

So we have m=("change in y")/("change in x")->1/2

As this is positive the graph 'goes up' reading left to right.

m=("change in y")/("change in x")->1/2 means that for every change of 1 in the y-axis the x-axis changes by 2.
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color(blue)("Answering the question")

color(brown)("Determine the y-intercept")

The plot crosses the y-axis at x=0 so by substitution we have:

y_("intercept")=1/2(0)-6

y_("intercept")=0-6

y_("intercept")=-6

y_("intercept")->(x,y)=(0,-6) color(green)(" Notice "-6" is the constant"
" "color(green)(darr)
" "y=mxcolor(green)(+c)

color(brown)("Determine the x-intercept")

The plot crosses the x-axis at y=0 so by substitution we have:

0=1/2x_("intercept")-6

Add 6 to both sides

6=1/2x_("intercept")

Multiply both sides by 2

12=x_("intercept")

x_("intercept")->(x,y)=(12,0)

Tony B