How do you graph $y = (\frac{2}{3}) x - 3$ $y= (2/3)x - 3$ ?

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How do you graph $y = (\frac{2}{3}) x - 3$ $y= (2/3)x - 3$ ?

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Answer 1 · 2016-02-26T19:35:02

The line goes through y at -3 and has a slope of $\frac{2}{3}$ $2/3$ .
enter image source here

Explanation:

The slope intercept equation of a line is
$y = m x + b$ $y=mx+b$
where $m$ $m$ is the slope and $b$ $b$ is the y intercept.

For the equation $y = \frac{2}{3} x - 3$ $y=2/3x -3$
The slope $m = \frac{2}{3}$ $m = 2/3$ and the y intercept $b = - 3$ $b = -3$

Begin by identifying the y intercept at -3 or the point (0,-3)
enter image source here
Next use the slope $m = \frac{2}{3}$ $m =2/3$ or $m = \frac{2 r i s e}{3 r u n}$ $m = (2 rise)/(3run)$ to determine the next point of the graph by going up +2 and to the right +3.

Now just draw the line through those two points.

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How do you graph $y = (\frac{2}{3}) x - 3$ $y= (2/3)x - 3$ ?

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