How do you graph $y=-2/3x-2$ using rise over run?

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Answer 1 · 2017-06-29T06:33:54

graph{y=-2/3x-2 [-10, 10, -5, 5]}

$y = -2/3x-2$

You put a point on $-2$ on the $y$ -axis. Then you go up $2$ and to the left $3$ because the left means negative. $((+2)/(-3))$

Or you can go down $2$ (negative) and to the right $3$ (positive).
$((-2)/(+3))$

You can't go left and down $((-)/(-))$ or up and right $(+/+)$ because the that will give a positive and the slope is negative.

How do you graph y=-2/3x-2y=-2/3x-2 using rise over run?