How do you graph $y = - 3 x - 3$ $y=-3x-3$ using rise over run?

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Answer 1 · 2018-07-18T02:15:44

$:.color(green)(" Slope " = m = "(rise) / (run)" = - 3$

$y = -3x - 3$

$y = mx + c " is the slope-intercept form"$

$color(crimson)("Slope " = m = tan theta = " (rise) / (run) = (y-intercept) / (x-intercept)"$

$"rise " = y " when " x = 0, run = x " when " y = 0$

$:. "when " x = 0, y = -3 * 0 - 3 = -3, "y-intercept " = -3$

$"Likewise, when " y = 0, 0 = -3x -3 " or x-intercept " = -1$

$:.color(green)(m= "(rise) / (run)" = (-3)/-1 = - 3 " as " theta " in II Quadrant"$

graph{- 3x - 3 [-10, 10, -5, 5]}

How do you graph y=-3x-3y=−3x−3y=-3x-3 using rise over run?