Question

How do you graph `y+4=0`?

Answer 1

See a solution process below:

Explanation:

We can solve this for `y` as:

`y + 4 - color(red)(4) = 0 - color(red)(4)`

`y + 0 = -4`

`y = -4`

This equation shows for each and every value of `x` then `y = -4`.

We can find two points to plot as:

For `x = 0` then `y = -4` or `(0, -4)`

For `x = 5` then `y = -4` or `(5, -4)`

graph{(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can now draw a line through the two points giving:

graph{(y+4)(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can this is a horizontal line from `-4` on the y-axis

Answer 2

Refer to the explanation.

Explanation:

Graph:

`y+4=0`

Solve for `y` by subtracting `4` from both sides of the equation.

`y=-4`

The graph will be a horizontal line at `y=-4` because all of the points will be `(x, -4)`, where `x=+-oo`.