The line is given in slope-intercept form, #y=mx+b#, where #m# is the slope and #b# is the #y#-coordinate of the #y#-intercept, #(0,b)#.
By inspection, we can see that the #y#-intercept is #(0,1)#.
The slope is #-4/3#, which we can think of as #(Deltay)/(Deltax)# or change in #y# over change in #x#. I think of it, in this case, as every move of 3 units to the right requires a move of 4 units down to stay on the line. So with that idea in mind, 3 units to the right from the #y#-intercept takes us to #x=3#. The corresponding 4 units down takes us to #y=1-4=-3#. So a second point on the line is #(3,-3)#.
Plot the points #(0,1)# and #(3,-3)# and connect them with a straight line.
