How do you graph #y=x+12# and #y=1/4x-3#?
1 Answer
Apr 8, 2017
See below:
Explanation:
Each of these equations is a line. Let's do them one at a time, then combine them.
For this, we can draw a line with the
graph{x+12 [-20.58, 7.9, -0.82, 13.42]}
We can graph the
graph{1/4x-3 [-7.77, 24.27, -7.41, 8.61]}
Put them together and we have:
graph{(y-(x+12))(y-(1/4x-3))=0 [-24.43, 4.04, -12.2, 2.04]}