How do you graph #y=-x+3/2# using the slope and intercept?
2 Answers
graph{y=-x+3/2 [-10, 10, -5.21, 5.21]}
This is the line that you should get from graphing
Explanation:
The format of this equation is
begin counting down one, and right one point. From there, you should create a graph similar to the one shown in the answer.
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Explanation:
The function
In the function you gave
The slope is
To graph this, you begin at the point
Essentially, the graph looks like this: (You can interact with the graph to get the exact points to plot)
graph{-x+3/2 [-10, 10, -5, 5]}