How do you graph #y+x=3#?

2 Answers
Jun 1, 2018

Refer Explanation.

Explanation:

#y+x=3#

#y=-x+3#

Comparing above equation with #y=mx+c# ,we get,

#m=-1# & #c=3#

Where, m=slope and c=y-intercept.

graph{3-x [-10, 10, -5, 5]}

We can also draw the graph by plotting random points satisfying equation of line.

Jun 1, 2018

#"see explanation"#

Explanation:

#"one way is to find the intercepts, that is where the"#
#"graph crosses the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry+0=3rArry=3larrcolor(red)"y-intercept"#

#y=0rArr0+x=3rArrx=3larrcolor(red)"x-intercept"#

#"Plot the points "(0,3)" and "(3,0)#

#"and draw a straight line through them for graph"#
graph{(y+x-3)((x-0)^2+(y-3)^2-0.04)((x-3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}