How do you put the equation $2 y - 3 x = 5$ $2y-3x=5$ into slope-intercept form, and graph the equation?

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Answer 1 · 2018-07-18T02:00:18

$Slope - Intercept form is y = (\frac{3}{2}) x + \frac{5}{2}$ $color(red)("Slope - Intercept form is " y = (3/2) x + 5/2)$

$:. color(brown)("Slope " = m = 3/2, " y-intercept " = c = 5/2$

$"Slope - Intercept form of an eqn is written as " y = m x + c$

$"where " m " is the slope and " c " the y-intercept"$

$m = tan theta = (y) / (x), c = y " when " x = 0$

$"Given equation is " 2y - 3x = 5$

$2y = 3 x + 5$

$color(red)(y = (3/2) x + 5/2)$

$:. color(brown)("Slope " = m = 3/2, " y-intercept " = c = 5/2$

graph{(3/2)x + (5/2) [-10, 10, -5, 5]}

How do you put the equation 2y-3x=52y−3x=52y-3x=5 into slope-intercept form, and graph the equation?