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What is $i^{2}$ $i^2$ ?

1 Answer

Apr 23, 2018

$- 1$ $-1$

Explanation:

The imaginary number, $i$ $i$ , is defined as: $i = \sqrt{- 1}$ $i=sqrt(-1)$ .

So, $i^{2} = {(\sqrt{- 1})}^{2} = - 1$ $i^2=(sqrt(-1))^2=-1$ .

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