What is #i^3#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Kevin B. Mar 22, 2015 #-i# #i^3# can be rewritten as # i^2 * i# Since #i^2 = -1, # #i^3 = -1 * i = -i# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? How do you simplify #i^-33#? See all questions in Powers of Complex Numbers Impact of this question 42306 views around the world You can reuse this answer Creative Commons License