What is the derivative of tanx^3tanx3? Calculus Differentiating Trigonometric Functions Special Limits Involving sin(x), x, and tan(x) 1 Answer Konstantinos Michailidis Oct 11, 2015 The derivative is 3x^2*sec^2(x^3)3x2⋅sec2(x3) where secxsecx is the secant function Explanation: The derivative is d(tanx^3)/dx=d(x^3)/dx*1/cos^2(x^3)=3x^2*(1/cos^2(x^3))=3x^2*sec^2(x^3)dtanx3dx=dx3dx⋅1cos2(x3)=3x2⋅(1cos2(x3))=3x2⋅sec2(x3) Answer link Related questions What are Special Limits Involving y=sin(x)y=sin(x)? How do you find the limit lim_(x->0)sin(x)/x ? How do you find the limit lim_(x->0)tan(x)/x ? What is the derivative of tanx/x? How do you differentiate g(x) =sin^2(x/6) ? How do you differentiate g(x) =(1+cosx)/(1-cosx) ? What is the derivative of tan(2x)? How do you differentiate f(x)=sinx/x? How do you differentiate f(x)=sinx/(1-cosx)? How do you differentiate f(x)=(x+2)/cosx? See all questions in Special Limits Involving sin(x), x, and tan(x) Impact of this question 25425 views around the world You can reuse this answer Creative Commons License