Question

How do you find the 4rd root of `81e^(60i)`?

Answer 1

`3e^(i(15+kpi/2))`

Four roots each for k=0,1,2,3

Explanation:

`z^4=81e^(i(60+2kpi))`
`z=root4(81)e^(i(60+2kpi)/4)=3e^(i(15+kpi/2))`