Question

A circle has a center at `(3 ,1 )` and passes through `(2 ,1 )`. What is the length of an arc covering `pi/8` radians on the circle?

Answer 1

length of arc `s=r*theta=1*pi/8=pi/8=0.392699`

Explanation:

From the given data:
A circle has a center at (3,1) and passes through (2,1). What is the length of an arc covering π/8 radians on the circle?

We need the radius r to compute for the arc

`r=sqrt((3-2)^2+(1-1)^2)=sqrt(1)=1`

`s=r*theta=1*pi/8=pi/8=0.392699`

God bless...I hope the explanation is useful.