A circle has a center at (7 ,3 ) and passes through (2 ,7 ). What is the length of an arc covering pi radians on the circle?

1 Answer
Feb 8, 2016

sqrt(41)pi

Explanation:

If the circle has a center at (7,3) and passes through (2,7)
it has a radius of r=sqrt((7-2)^2+(3-7)^2)=sqrt(41)

The length of an arc covering pi radians is half the length of the circumference
color(white)("XXX")(2pir)/2 = pir

So in this case, the length of the arc is
color(white)("XXX")pisqrt(41)