Question

A circle has a center at `(7 ,6 )` and passes through `(2 ,1 )`. What is the length of an arc covering `pi/12` radians on the circle?

Answer 1

1.8512 units

Explanation:

Using distance formula, solve for the distance between (7,6) and (2,1). That would be `sqrt((7-2)^2 +(6-1)^2` equal to `5sqrt2` units. Since, arc length `S = rtheta` where r is the radius and `theta` is in radians. Multiplying: `5sqrt2 xx pi/12 = 1.8512 units`